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Question
A pendulum performs S.H.M. with period `sqrt3` second in a stationary lift. If lift moves up with acceleration `"g"/3`, the period of pendulum is ______. (g = acceleration due to gravity)
Options
2.5 second
2.00 second
1.5 second
1.75 second
MCQ
Fill in the Blanks
Solution
A pendulum performs S.H.M. with period `sqrt3` second in a stationary lift. If lift moves up with acceleration `"g"/3`, the period of pendulum is 1.5 second.
Explanation:
T = `sqrt3` a = `"g"/3`
T' = `2pi sqrt(l/("g" + "g"/3))`
`therefore "T'"/"T" = sqrt("g"/("4g"//3)) = sqrt3/2`
T' = `sqrt3 xx sqrt3/2 = 3/2` = 1.5 sec
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Simple Pendulum
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