Question

A person can throw a ball up to a maximum range of 100 m. How high above the ground he can throw the same ball?

Options

• 25 m

• 50 m

• 100 m

• 200 m

Answer 1

50 m

Explanation:

For maximum range, R = `u^2/g`

Hence, `u^2/g = 100`

u² = 100 g ............(1)

For maximum, height, H = `u^2/(2g)` ......(2)

By using equations (1) in (2), we have;

H = `(100g)/(2g) = 50 m`