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Question
A photon of wavelength 3315 Å falls on a photocathode and an electron of energy 3 x 10-19 J is ejected. The threshold wavelength of photon is [Planck's constant (h) = 6.63 x 10-34 J.s, velocity of light (c) = 3 x 108 m/s] ____________.
Options
5000 Å
3315 Å
6630 Å
1130 Å
MCQ
Fill in the Blanks
Solution
A photon of wavelength 3315 Å falls on a photocathode and an electron of energy 3 x 10-19 J is ejected. The threshold wavelength of photon is 6630 Å.
Explanation:
`phi_0 = "hc"/lambda - "E"`
`= (6.63 xx 10^-34 xx 3 xx 10^8)/(3315 xx 10^-10) - 3 xx 10^-19)`
`= (6 - 3) xx 10^-19`
`= 3 xx 10^-19`
`lambda_0 = "hc"/phi_0`
`= (6.63 xx 10-34 xx 3 xx 10^8)/(3 xx 10^-19) approx 6630 Å`
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De Broglie Hypothesis
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