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Question
A piece of wood of uniform cross section and height 15 cm floats vertically with its height 10 cm in water and 12 cm in spirit. Find the densities of wood and spirit.
Solution
Let densities of water, wood and spirit are ρ, ρw and ρs respectively.
Let A be the area of the wooden block.
Total volume of the wooden block is, V = 15A
1. Mass of wood = Mass of water displaced by the wood
Vρwg = A×10×ρ×g
ρw = `(A xx 10 xx ρ xx "g")/(15 xx A xx "g") = 0.67` g/cm3
2. Mass of the wood = Mass of then spirit displaced
Vρwg = A×12×ρs×g
ρs = 0.83 g/cm3
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