Advertisements
Advertisements
Question
If the density of ice is 0.9 g cm-3, then what portion of an iceberg will remain below the surface of water in sea? (Density of sea water = 1.1 g cm-3)
Solution
Density of ice (ρ1)= 0.9 gcm-3
Density of sea water (ρs) = 1.1 gcm-3
Let the total volume of the iceberg be V and the volume of immersed portion be v.
According to the law of floatation,
`"v"/"V" = ρ_1/ρ_s`
or , `"v"/"V" = 0.9/1.1 = 9/11`
or , v = `9/11`V
Thus , ice floats with `9/11`th part of its volume above the surface sea water.
RELATED QUESTIONS
Assuming the density of air to be 1.295 kg m-3, find the fall in barometric height in mm of Hg at a height of 107 m above the sea level. Take density of mercury = 13.6 × 103 kg m-3.
Express the relationship between the C.G.S. and S.I. units of density.
'The density of iron is 7800 kg m-3'. What do you understand by this statement?
Complete the following sentence.
Density of water is .... ... kg m-3.
A body of mass 50 g is floting in water. What is the apparent weight of body in water? Explain your answer.
A solid body weighs 2.10 N. in air. Its relative density is 8.4. How much will the body weigh if placed
(1) in water,
(2) in liquid of relative density 1.2?
Select the correct option:
With the increase in the density of the fluid, the upthrust experienced by a body immersed in it:
Select the correct option:
A body has density 9.6 gcm -3. Its density in SI system is:
A wooden cube of side 10 cm has a mass of 700 g. It will float in the water with:
(a) Half of its volume inside the water
(b) 3 cm height above the water surface
(c) 7 cm height above the water surface
(d) Just inside the water surface.
