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Question
A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth's surface is 11 km s-1 , the escape velocity from the surface of the planet would be ______.
Options
1.1 km s-1
11 km s-1
110 km s-1
0.11 km s-1
Solution
A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth's surface is 11 km s-1, the escape velocity from the surface of the planet would be 110 km s-1.
Explanation:
`("v"_"e")_"p"/("v"_"e")_"e" = sqrt((2"GM"_"p")/"R"_"p")/sqrt((2"GM"_"e")/"R"_"e")`
= `sqrt("M"_"p"/"M"_"e"xx"R"_"e"/"R"_"p")`
= `sqrt((10"M"_"e")/"M"_"e"xx"R"_"e"/("R"_"e"//10)`
= 10
∴ (ve)p = 10 × (ve)e
= 10 × 11
= 110 km/s