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Question
A point isotropic light source of power P = 12 watts is located on the axis of a circular mirror of radius R = 3 cm. If the distance of the source from the centre of the mirror is a = 39 cm and the reflection coefficient of the mirror is α = 0.70 then the force exerted by the light ray on the mirror is ______ × 10-10 N.
Options
1.00
2.00
3.00
4.00
Solution
A point isotropic light source of power P = 12 watts is located on the axis of a circular mirror of radius R = 3 cm. If the distance of the source from the centre of the mirror is a = 39 cm and the reflection coefficient of the mirror is α = 0.70 then the force exerted by the light ray on the mirror is 1.00 × 10-10 N.
Explanation:
`[(P/(4pia^2) xx piR^2)/(hv)][70/100 xx (2hv)/c + 30/100 xx (hv)/c]`
= `1 xx 10^-10` N