Advertisements
Advertisements
Question
A pole stands vertically inside a triangular park ΔABC. If the angle of elevation of the top of the pole from each corner of the park is same, then in ΔABC the foot of the pole is at the
Options
centroid
circumcentre
incentre
orthocentre
MCQ
Solution
circumcentre
Explanation:
Let OP = Pole, ∠PAO = ∠PBO = ∠PCO = `alpha`
In ΔOPB, `(OP)/(OB) = tan alpha`
⇒ OB = OP cot `alpha` ......(i)
Similarly, OA = OP cot `alpha` ......(ii)
And OC = OP cot `alpha` ......(iii)
From equations (i), (ii) and (iii)
OA = OB = OC ⇒ O is the point of circumcentre of the triangle ABC.
shaalaa.com
Determinants
Is there an error in this question or solution?