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A proton and a Li3+ nucleus are accelerated by the same potential. If λLi and λP denote the de Broglie wavelengths of Li3+ and proton respectively -

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A proton and a Li3+ nucleus are accelerated by the same potential. If λLi and λP denote the de Broglie wavelengths of Li3+ and proton respectively, then the value of `λ_("Li")/(λ_"P")` is x × 10−1. The value of x is ______. [Rounded-off to the nearest integer]

[Mass of Li3+ = 8.3 mass of proton]

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Solution

A proton and a Li3+ nucleus are accelerated by the same potential. If λLi and λP denote the de Broglie wavelengths of Li3+ and proton respectively, then the value of `λ_("Li")/(λ_"P")` is x × 10−1. The value of x is 2.

Explanation:

From the de-Broglie wavelength, we get

λ = `"h"/(sqrt(2"meV"))`

∴ `λ_("Li"^(3+))` = `"h"/(sqrt(2"m"_("Li"^(3+))"eV"))`;

λP = `"h"/(sqrt(2"m"_"P""eV"))`

By the problem, `"V"_("Li"^(3+))` = VP

`"m"_("Li"^(3+))` = 8.3 mp

∴ `λ_("Li"^(3+))/(λ_"P") = sqrt("m"_"P"("e") xx "V")/(sqrt(8.3 "m"_"P" xx 3"e" xx "V"))`

= `1/sqrt(8.3 xx 3)`

= `1/5`

= 0.2

= 2 × 10−1

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