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Question
A proton and a Li3+ nucleus are accelerated by the same potential. If λLi and λP denote the de Broglie wavelengths of Li3+ and proton respectively, then the value of `λ_("Li")/(λ_"P")` is x × 10−1. The value of x is ______. [Rounded-off to the nearest integer]
[Mass of Li3+ = 8.3 mass of proton]
Options
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Solution
A proton and a Li3+ nucleus are accelerated by the same potential. If λLi and λP denote the de Broglie wavelengths of Li3+ and proton respectively, then the value of `λ_("Li")/(λ_"P")` is x × 10−1. The value of x is 2.
Explanation:
From the de-Broglie wavelength, we get
λ = `"h"/(sqrt(2"meV"))`
∴ `λ_("Li"^(3+))` = `"h"/(sqrt(2"m"_("Li"^(3+))"eV"))`;
λP = `"h"/(sqrt(2"m"_"P""eV"))`
By the problem, `"V"_("Li"^(3+))` = VP
`"m"_("Li"^(3+))` = 8.3 mp
∴ `λ_("Li"^(3+))/(λ_"P") = sqrt("m"_"P"("e") xx "V")/(sqrt(8.3 "m"_"P" xx 3"e" xx "V"))`
= `1/sqrt(8.3 xx 3)`
= `1/5`
= 0.2
= 2 × 10−1