Question

A proton is accelerated in a cyclotron in which the magnetic induction is 0.6 Wb/ m²  Find the cyclotron frequency.

(Given: m_p = 1.673 x 10^-27 kg, e = 1.6 x 10^-19 C)

Answer 1

Given: 

B = 0.6 Wb/ m², 0

m_p= 1.673 x 10^-27 kg,

e = 1.6 x 10^-I9 C

To find:

Frequency ( n) = ?

Formula:

`n = (qB)/(2pim) = (eB)/(2pim)`

From formula,

`n =(1.6 xx 10^-19 xx 0.6)/ (2 xx 3 .1 42 xx 1.673 xx 10^-27)`

`= 0.96/10.513 xx 10^8 = 9.13 xx 10^6`

∴ Frequency n = 9.13 × 10⁶ Hz