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Question
A radioctive sample decays `7/8` times its original quantity in 15 minutes. The half-life of the sample is ______.
Options
5 min
7.5 min
15 min
30 min
MCQ
Fill in the Blanks
Solution
A radioctive sample decays `7/8` times its original quantity in 15 minutes. The half-life of the sample is 5 min.
Explanation:
Remaining = `1/8`
So \[\ce{N_0->[15min]\frac{N_0}{8}=\frac{N_0}{2^3}}\]
So, 3t1/2 = 15 min ⇒ t1/2 = 5 min
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