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Question
A random variable X has following probability distribution
X = x | 1 | 2 | 3 | 4 | 5 | 6 |
P(X = x) | K | 3K | 5K | 7K | 8K | K |
Then P(2 ≤ X < 5) = _____.
Options
`3/5`
`7/25`
`23/25`
`24/25`
MCQ
Solution
`3/5`
Explanation:
We know that, ∑ pi = 1
⇒ k + 3k + 5k + 7k + 8k + k = 1
⇒ 25k = 1
⇒ k = `1/25`
Now, P(2 ≤ X < 5)
= P(X = 2) + P(X = 3) + P(X = 4)
= 3k + 5k + 7k = 15k
= `15 xx 1/25 = 3/5`
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