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Question
A random variable X has the following has the following:
X = x | –2 | –1 | 0 | 1 | 2 | 3 | 4 |
P(X = x) | 6k | 8k | 5k | 4k | 6k | 11k | 7k |
Then, the value of P(–1 < X < 3) is ______.
Options
`26/49`
`15/47`
`23/49`
`34/49`
MCQ
Fill in the Blanks
Solution
A random variable X has the following has the following:
X = x | –2 | –1 | 0 | 1 | 2 | 3 | 4 |
P(X = x) | 6k | 8k | 5k | 4k | 6k | 11k | 7k |
Then, the value of P(–1 < X < 3) is `15/47`.
Explanation:
Since `sum_(x = -2)^4 "P"("X" = x)` = 1,
6k + 8k + 5k + 4k + 6k + 11k + 7k = 1
⇒ 47k = 1
⇒ k = `1/47`
∴ P(–1 < X < 3) = P(X 0 + P(X = 1) + P(X = 2)
= 5k + 4k + 6k
= 15k
= `15/47`
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