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Question
A random variable x has to following probability distribution.
X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
P(x) | 0 | k | 2k | 2k | 3k | k2 | 2k2 | 7k2 + k |
Determine
Options
`3/10`
`17/100`
`2/10`
`1/10`
MCQ
Solution
`1/10`
Explanation:
Sum of probabilities = 1
i.e., 0 + k + 2k + 2k + 3k + k2 + 2k2 + 7k2 + k = 1
or 10k2 + 9k = 1 or 10k2 + 9k – 1 = 0
(k + 1) (10k – 1) = 0
∴ k = – 1 or k = `1/10`
∴ k ≠ – 1
∴ k = `1/10`
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