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Maharashtra State BoardSSC (English Medium) 7th Standard

A rectangle is (8x + 5) cm long and (5x + 3) cm broad. Find its area. - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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Question

A rectangle is (8x + 5) cm long and (5x + 3) cm broad. Find its area.

Sum

Solution

Length of the rectangle = (8x + 5) cm

Breadth of the rectangle = (5x + 3) cm

Area of rectangle = length × breadth

= (8x + 5)(5x + 3)

= 8x(5x + 3) + 5(5x + 3)

= 8x × 5x + 8x × 3 + 5 × 5x + 5 × 3

= 40x2 + 24x + 25x + 15

= 40x2 + 49x + 15

So, area of rectangle is (40x2 + 49x + 15) cm2.

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Chapter 8: Algebraic Expressions and Operations on Them - Practice Set 35 [Page 59]

APPEARS IN

Balbharati Mathematics [English] 7 Standard Maharashtra State Board
Chapter 8 Algebraic Expressions and Operations on Them
Practice Set 35 | Q 2 | Page 59
Balbharati Integrated 7 Standard Part 2 [English Medium] Maharashtra State Board
Chapter 3.4 Algebraic Expressions and Operations on them
Practice Set 35 | Q 2. | Page 72
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