Question

A rectangular coil of length 0.12 m and width 0.1 m having 100 turns of wire is suspended vertically in a uniform magnetic field of strength 0.4 Wb/m². The coil carries a current of 2.5 A. If the plane of the coil is inclined at an angle of 30° with the direction of the field, the torque required to keep the coil in stable equilibrium will be ____________.

Options

• 2.12 Nm

• 0.15 Nm

• 1.04 Nm

• 0.24 Nm

Answer 1

A rectangular coil of length 0.12 m and width 0.1 m having 100 turns of wire is suspended vertically in a uniform magnetic field of strength 0.4 Wb/m². The coil carries a current of 2.5 A. If the plane of the coil is inclined at an angle of 30° with the direction of the field, the torque required to keep the coil in stable equilibrium will be 1.04 Nm.

Explanation:

`tau ="NAIB sin" theta`

`= 100 xx 0.12 xx 2.5 xx 0.4 xx "sin 60°"`

`= 1.04  "Nm"`