Question

A resistance of 3Ω is connected in parallel to a galvanometer of resistance 297Ω. Find the fraction of current passing through the galvanometer.

Answer 1

I_gG = (I - I_g)S

From formula,

`G/S=(I-I_g)/I_g=I/I_g-1`

`G/S+1=I/I_g`

`(G+S)/S=I/I_g`

`I_g/I=S/(S+G)`

`=3/(3+297)`

`I_g/I=3/300=[3/300xx100]%`

`I_g/I=1%`

The fraction of current passing through the galvanometer is 1 %.