Question

A ring consisting of two parts ADB and ACB of same conductivity K carries an amount of heat H. The ADB part is now replaced with another metal keeping the temperatures T₁ and T₂ constant. The heat carried increases to 2H. What should be the conductivity of the new ADB part? (Given `"ACB"/"ADB"` = 3)

 

Options

• `7/3`K

• 2 K

• `5/2`K

• 3 K

Answer 1

`bb(7/3 "K")`

Explanation:

H = `"KAT"/"l" (1+1/3)`

2H = `"AT"/"l"("K'"+"K"/3)`

solving = K' = `(7"K")/3`