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Question
A rod I m long is acted upon by a couple as shown in the figure. The moment of couple is τ Nm. If the force at each end of the rod, then magnitude of each force is ______.
(sin 30° = cos 60° = 0.5)
Options
`tau/l`
`l/(2tau)`
`(2tau)/l`
`(2l)/tau`
MCQ
Fill in the Blanks
Solution
A rod I m long is acted upon by a couple as shown in the figure. The moment of couple is τ Nm. If the force at each end of the rod, then magnitude of each force is `underline((2tau)/l)`.
Explanation:
Length of rod = I
Moment of couple,
τ = FI sin θ
`therefore "F" = tau/(l sin theta) = tau/(l sin 30^circ) = tau/(l xx 1/2)`
Force, F = `(2tau)/l`
shaalaa.com
Couple and Its Torque
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