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Question
A rod of weight W is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is ____________.
Options
`"Wx"/d`
`"Wd"/"x"`
`"W (d - x)"/"x"`
`"W (d - x)"/"d"`
MCQ
Fill in the Blanks
Solution
A rod of weight W is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is `"W (d - x)"/"d"`.
Explanation:
For equilibrium,
N1 d = W (d - x)
`therefore "N"_1 = "W (d - x)"/"d"`
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Mechanical Equilibrium
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