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Question
A sample of gas absorbs 4000 kJ of heat and surrounding does 2000 J of work on sample. What is the value of ∆U?
Options
4002 kJ
6000 kJ
4000 kJ
2000 kJ
MCQ
Solution
4002 kJ
Explanation:
Given, q = + 4000 kJ ........(heat absorbed)
W = + 2000 J .........(work done by surrounding)
= 2 kJ or `(2000/1000)` kJ
Using the first law of thermodynamics,
ΔU = q + W
= (4000 + 2) kJ
= 4002 kJ
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First Law of Thermodynamics
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