Question

A see-saw of length 6 m is pivoted at its centre. A child of mass 20 kg is sitting at one of its ends. Where should another child, of mass 30 kg, sit on the other end from the centre of see-saw, so that it is balanced?

Options

• 1 m

• 3 m

• 2 m

• 4 m

Answer 1

2 m

Explanation:

∴ 20 × 3 = x × 30

`therefore x=60/30=2  "m"`