Question

A set of 56 tuning forks are arranged in series of increasing frequencies. If each fork gives 4 beats with preceding one and the frequency of the last is twice than than that of first, then frequency of the first fork is ____________.

Options

• 110 Hz

• 220 Hz

• 224 Hz

• 448 Hz

Answer 1

A set of 56 tuning forks are arranged in series of increasing frequencies. If each fork gives 4 beats with preceding one and the frequency of the last is twice than than that of first, then frequency of the first fork is 220 Hz.

Explanation:

n₅₆ = n₁ + (56- 1)4

Also, n₅₆ = 2n₁

∴ 2n₁ = n₁ + 55 x 4

∴ n₁ = 220 Hz