Question

A short electric dipole bas a dipole moment of 16 x 10^-9 C m. The electric potential due to the dipole at a point at a distance of 0.6 m from the centre of the dipole, situated on a line making an angle of 60° with the dipole axis is: ____________. ${\displaystyle (\frac{1}{4\pi {\epsilon }_0}=9\times {10}^9 {\text{Nm}}^2/{\text{C}}^2)}$

Options

• 200 V

• 400 V

• zero

• 50 V

Answer 1

A short electric dipole bas a dipole moment of 16 x 10^-9 C m. The electric potential due to the dipole at a point at a distance of 0.6 m from the centre of the dipole, situated on a line making an angle of 60° with the dipole axis is: 200 V.

Explanation:

Electric potential,

${\displaystyle \text{V}=\frac{1}{4\pi {\epsilon }_0}\frac{\text{p cos}\theta }{{\text{r}}^2}}$

${\displaystyle =9\times {10}^9\times \frac{16\times {10}^{-9}\times \cos 60°}{{\left(0.6\right)}^2}}$

${\displaystyle =9\times {10}^9\times \frac{16\times {10}^{-9}\times 1}{{\left(0.6\right)}^2\times 2}}$

${\displaystyle =200 \text{V}}$