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Question
A short electric dipole bas a dipole moment of 16 x 10-9 C m. The electric potential due to the dipole at a point at a distance of 0.6 m from the centre of the dipole, situated on a line making an angle of 60° with the dipole axis is: ____________. `(1/(4piepsilon_0) = 9 xx 10^9 "Nm"^2// "C"^2)`
Options
200 V
400 V
zero
50 V
MCQ
Fill in the Blanks
Solution
A short electric dipole bas a dipole moment of 16 x 10-9 C m. The electric potential due to the dipole at a point at a distance of 0.6 m from the centre of the dipole, situated on a line making an angle of 60° with the dipole axis is: 200 V.
Explanation:
Electric potential,
`"V" = 1/(4 piepsilon_0) ("p cos" theta)/"r"^2`
`= 9 xx 10^9 xx (16 xx 10^-9 xx cos 60°)/(0.6)^2`
`= 9 xx 10^9 xx (16 xx 10^-9 xx 1)/((0.6)^2 xx 2)`
`= 200 "V"`
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