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Question
A simple pendulum has a time period T1 when on the earth's surface and T2 when taken to a height R above the earth's surface, where R is the radius of the earth. The value of T2 / T1 is ______.
Options
1
`sqrt2`
`sqrt3`
2
MCQ
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Solution
A simple pendulum has a time period T1 when on the earth's surface and T2 when taken to a height R above the earth's surface, where R is the radius of the earth. The value of T2 / T1 is 2.
Explanation:
If the acceleration due to gravity is g at the surface of the earth, then · at height R, its value becomes
`"g'" = "g"(R/(R+h))^2= "g"/4`
`"T"_1=2 π sqrt(l/g)`
∴ `"T"_2= 2 π sqrt(l/(g/4)`
∴ `"T"_2=2xx2 π sqrt(l/g)`
∴ `"T"_2=2"T"_1`
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Simple Pendulum
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