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Question
A solenoid 3.142m long and 5.0 cm in diameter has two layers of windings of 500 turns each and carries a current of 5A. Calculate the magnetic induction at its centre along the axis.
Solution
Given:
Length of solenoid, l = 3.142m
Diameter, d = 5.0cm = 5 × 10-2m
Radius, r = 2.5cm = 2.5 × 10-2m
No. of turns, N = 2 × 500 = 1000
Current, I = 5A
To calculate:
The magnetic induction at its centre along the axis.
Magnetic Induction, B = ?
Formula:
B = μonI
Solution:
`"B"=mu_o("N"/"l")"I"`
`therefore"B"=(4pixx10^-7xx1000xx5)/3.142`
`therefore"B"=2xx10^-3 "T"`
Hence, the magnetic induction at the centre of the circular loop along its axis is 2 × 10-3T.
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