Question

A solenoid of length 0.6 m has a radius of 2 cm and is made up of 600 turns If it carries a current of 4 A, then the magnitude of the magnetic field inside the solenoid is:

Options

• 6.024 × 10⁻³ T

• 8.024 × 10⁻³ T

• 5.024 × 10⁻³ T

• 7.024 × 10⁻³ T

Answer 1

5.024 × 10⁻³ T

Explanation:

Here, n = `600/0.6` = 1000 turns/mI = μA

I = 0.6 m, r = 0.02 m

∵ `1/"r"` = 30 i.e. I >> r

Hence, we can use long solenoid formula, then

∴ B = μ₀nI = 4 × 10⁻⁷ × 10³ × 4

= 50.24 × 10⁻⁴

= 5.024 × 10⁻³ T