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Question
Answer the following.
A solid metal sphere of volume 0.31 m3 is dropped in an ocean where water pressure is 2 × 107 N/m2. Calculate change in volume of the sphere if the bulk modulus of the metal is 6.1 × 1010 N/m2.
Solution
Given: V = 0.31 m3, dP = 2 × 107 N/m2, K = 6.1 × 1010 N/m2
To find: Change in volume (dV)
Formula: K = V × `"dP"/"dV"`
Calculation: From formula,
dV = `("V" xx "dP")/"K"`
∴ dV = `(0.31 xx 2 xx 10^7)/(6.1 xx 10^10) ~~ 10^-4 "m"^3`
The change in volume of the sphere is 10-4 m3.
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