Advertisements
Advertisements
Question
A solid weighs 105 kgf in air. When completely immersed in water, it displaces 30,000 cm3 of water, calculate relative density of solid.
Solution
Weight of solid in air =105 kgf
Volume of solid = Volume of water displaced = 30000 cm3
= 30000 x 10-6 m3 = 0.03 m3
pw = Density of water = 1000 kgm-3
Wt. of water displaced by solid.
`"V"rho_"w""g" = 0.03 xx 1000 xx "g" = 30 "kgf"`
R.D. of solid = `"Weight of solid in air"/"Weight of water displaced by solid"`
`= 105/30 = 3.5`
APPEARS IN
RELATED QUESTIONS
A body of volume V and density ρ is kept completely immersed in a liquid of density ρL. If g is the acceleration due to gravity, then write expressions for the following:
(i) The weight of the body, (ii) The upthrust on the body,
(iii) The apparent weight of the body in liquid, (iv) The loss in weight of the body.
Complete the following sentence.
Density in kg m-3 = ............ × density in g cm-3
The unit of relative density is :
Calculate the mass of a body whose volume is 2 m3 and relative density is 0.52.
A body weighs 20 gf in air and 18.0 gf in water. Calculate the relative density of the material of the body.
A body of mass 70 kg, when completely immersed in water, displaces 20,000 cm3 of water. Find: (i) The weight of body in water and (ii) The relative density of material of the body.
A piece of metal weighs 44.5 gf in air, 39.5 gf in water. What is the R.D. of the metal?
A body of volume 100 cm3 weighs 1 kgf in air. Calculate its weight in water. What is its relative density?
