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Question
A solid weighs 2.10 N in air. It has a relative density of 8.4. How much will the body weigh if placed: In a liquid of relative density 1.2
Solution
Relative density of liquid =1.2
We know
Relative density of liquid = Loss of weight of solid in liquid/loss of weight of solid in water.
Loss of weight of solid in liquid = Relative density X loss of weight of solid in water.
Loss of weight of solid in liquid = 1.2 X 0.25 = 0.3 N.
Weight of solid in liquid = weight of solid in the air - loss of weight of solid in a liquid.
Weight of solid in liquid = 2.10 - 0.3 = 1.8 N.
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