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A sparingly soluble salt having general formula AXxp+ BXyq− and molar solubility S is in equilibrium with its saturated solution. Derive a relationship between the solubility and solubility product - Chemistry

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Question

A sparingly soluble salt having general formula \[\ce{A^{p+}_x B^{q-}_y}\] and molar solubility S is in equilibrium with its saturated solution. Derive a relationship between the solubility and solubility product for such salt.

Chemical Equations/Structures

Solution

The equation can be written as-

\[\ce{A^{p+}_x B^{q-}_y ⇌ xA^{p+} (aq) + yB^{q-} (aq)}\]

S moles of A and B dissolves to give x S moles of Ap+ and y Bq-.

\[\ce{K_{sp} = [A^{p+}] [Bq^{-}]^y}\]

= `[x^5]^x [y^5]^y`

= `x^{x}y^{y} 5^{x + y}`

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Concept of Solubility Equilibria of Sparingly Soluble Salts
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Chapter 7: Equilibrium - Multiple Choice Questions (Type - I) [Page 96]

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NCERT Exemplar Chemistry [English] Class 11
Chapter 7 Equilibrium
Multiple Choice Questions (Type - I) | Q 53 | Page 96

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