Question

A spring of force constant of 400 N/m is loaded with a mass of 0.25 kg. The amplitude of oscillations is 4 cm. When mass comes to the equilibrium position. Its velocity is ______.

Options

• 16 m/s

• 1.6 m/s

• 0.16 m/s

• 0.016 m/s

Answer 1

A spring of force constant of 400 N/m is loaded with a mass of 0.25 kg. The amplitude of oscillations is 4 cm. When mass comes to the equilibrium position. Its velocity is 1.6 m/s.

Explanation:

Given, mass, m = 0.25 kg

Force constant, k = 400 N/m

The amplitude of oscillations, A = 4 cm = 0.04 m

Angular frequency, `omega = sqrt(k/m) = sqrt(400/0.25) = sqrt1600 = 40` rad/s

Velocity at equilibrium position = ωA = 40 × 0.04 = 1.6 m/s