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Question
A straight wire of length 50 cm carrying a current of 6 A is suspended in mid-air by a uniform magnetic field of 0.4 T (as shown in figure). The mass of the wire is ______.
(g = 10` "ms"^-2`)
Options
0.12 g
125 g
62.5 g
100 g
MCQ
Fill in the Blanks
Solution
A straight wire of length 50 cm carrying a current of 6 A is suspended in mid-air by a uniform magnetic field of 0.4 T (as shown in figure). The mass of the wire is 0.12 g.
Explanation:
F = `"I"/"B"` sin `theta`
`theta` = `90^circ`
`therefore "sin" 90^circ` =1
`therefore "F" = "I"/"B"`
`therefore "mg" = "I"/"B"`
m = `("I"/"B")/"g"`
= `(6xx50xx10^-2xx0.4)/10` = 0.12 g
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Magnetic Force on a Wire Carrying a Current
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