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Question
A sum of money becomes 1,331 times in 3 years as compound interest. The rate of interest is-
Options
8%
7.5%
10%
50%
MCQ
Solution
10%
Explanation:
If principal = ₹1000, amount = ₹1331
∴ A = `"P" (1 + "R"/100)^"T"`
⇒ `1331/1000 = (1 + "R"/100)^3`
⇒ `(11/10)^3 = (1 + "R"/100)^3`
⇒ `1 + "R"/100 = 11/10`
⇒ `"R"/100 = 1/10`
⇒ `"R" = 1/10 xx 100`
= 10%
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Simple and Compound Interest (Entrance Exam)
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