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Question
A toroid is a long coil of wire wound over a circular core. The major radius and cross-sectional radius of the toroid are R and r, respectively. The coefficient of mutual induction of the toroid is ______.
(The magnetic field in it is uniform, N = number of turns, R >> r, μ0 = permeability of free space)
Options
`(mu_0NR)/(2r)`
`(mu_0N^2R^2)/(2r)`
`(mu_0Nr)/(2R)`
`(mu_0N^2r^2)/(2R)`
Solution
A toroid is a long coil of wire wound over a circular core. The major radius and cross-sectional radius of the toroid are R and r, respectively. The coefficient of mutual induction of the toroid is `unerlinebb((mu_0N^2R^2)/(2r))`.
Explanation:
The coefficient of mutual induction is given by,
`M = (mu_0N_1N_2A)/l` ...........(i)
where µ0 is the permeability of free space,
N1 is the number of turns in the primary coil,
N2 is the number of turns in the secondary coil,
A is the common area of cross-section and l is the length of coils.
Thus, for toroid, the Eq. (i) is given as,
M = `(mu_0N . N . piR^2)/(2pir) = (mu_0N^2R^2)/(2r)`
`[(∵ N_1 = N_2 = N),(A = piR^2"," l = 2pir)]`
where R is the major radius and r is the minor radius.