Advertisements
Advertisements
Question
A train blowing the whistle moves with a constant velocity 'V' away from an observer standing on the platform. The ratio of the natural frequency of the whistle 'n' to the apparent frequency is 1.2 : 1. If the train is at rest and the observer moves away from it at the same velocity 'V', the ratio of 'n' to the apparent frequency is ______.
Options
1.52 : 1
0.51 : 1
2.05 : 1
1.25 : 1
Solution
A train blowing the whistle moves with a constant velocity 'V' away from an observer standing on the platform. The ratio of the natural frequency of the whistle 'n' to the apparent frequency is 1.2 : 1. If the train is at rest and the observer moves away from it at the same velocity 'V', the ratio of 'n' to the apparent frequency is 1.25 : 1.
Explanation:
In the 1st case, the apparent frequency is given by
`"n_1"="n"("V"_s)/("V"_s+"V")`
where Vs is the velocity of sound.
`therefore"n"/"n"_1=1.2=("V"_s+"V")/"V"_s`
∴ 1.2 Vs = Vs + V
∴ 1.2 Vs - Vs = V
V = 0.2 Vs
In the second case,
`"n"_2="n"(("V"_s-"V")/"V"_s)`
`therefore"n"/"n"_2=("V"_s)/("V"_s-"V")="V"_s/("V"_s-0.2 "V"_s)`
`=1/0.8=1.25`