Question

A transformer having efficiency of 80% is working on 200 V and 6 kW power supply. If the current in the secondary coil is 6 A, the voltage across the secondary coil and the current in the primary coil respectively are ____________.

Options

• 300 V, 15 A

• 450 V, 30 A

• 800 V, 30 A

• 600 V, 15 A

Answer 1

800 V, 30 A

Explanation:

`"Power output" = 6 xx 80/100 = 4.8  "kW"`

`"I"_"P" = 6  "A"`

`therefore "V"_"S" = (4.8 xx 10^3)/6 = 800`

` "V" and "I"_"P"`

` = (6 xx 10^3)/200 = 30  "A"`