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Question
A transformer operating at primary voltage 8 kV and secondary voltage 160 V serves a load of 80 kW. Assuming the transformer to be ideal with purely resistive load and working on unity power factor, the loads in the primary and secondary circuit would be:
Options
800 Ω and 1.06 Ω
10 Ω and 500 Ω
800 Ω and 0.32 Ω
1.06 Ω and 500 Ω
MCQ
Solution
800 Ω and 0.32 Ω
Explanation:
`((8xx10^3)^2)/"R"_"P"` = 80 × 103 `[∵ "P" = "V"^2/"R"]`
⇒ RP = 800 Ω
Similarly, `(160)^2/"R"_"S"` = 80 × 103
⇒ RS = 0.32 Ω
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