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Question
A TV tower has a height of 100 meter. If the coverage range is to be made three times then the height of the tower should be increased by.
Options
500 m
600 m
700 m
800 m
MCQ
Solution
800 m
Explanation -
`"Coverage range" ∝ sqrt"height of power"`
`"Coverage" ∝ sqrt100` ...(i)
Let h be height of tower to tripple coverage
`3 xx "coverage" ∝ sqrt"h"` ...(ii)
dividing eqn (i) and (ii)
`1/3 = sqrt(100/"h") => "h" = 900`
As a result, the height should be increased by 900 - 100 = 800 metres.
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