Question

A two digit number is to be formed from the digits 2, 3, 5 without repetition of the digits. Complete the following activity to find the probability that the number so formed is an odd number.

Activity:

Let S be the sample space.

∴ S = {23, 25, 32, `square`, 52, 53}

∴ n(S) = `square`

Event A: The number so formed is an odd number.

∴ A = {23, 25, `square`, 53}

∴ n(A) = 4

∴ P(A) = `(square)/(n(S))`  .....(Formula)

∴ P(A) = `(square)/(6)`

∴ P(A) = `(square)/(3)`

Answer 1

Let S be the sample space.

∴ S = {23, 25, 32, \[\boxed{35}\], 52, 53}

∴ n(S) = \[\boxed{6}\]

Event A: The number so formed is an odd number.

∴ A = {23, 25, \[\boxed{35}\], 53}

∴ n(A) = 4

∴ P(A) = \[\frac{\boxed{n(A)}}{n(S)}\]  .....(Formula)

∴ P(A) = \[\frac{\boxed{4}}{6}\]

∴ P(A) = \[\frac{\boxed{2}}{3}\]