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Question
A uniform metal wire has length 'L', mass 'M', and density 'ρ'. It is under tension 'T' and 'v' is the speed of transverse wave along the wire. The area of cross-section A of the wire is ______
Options
T2ρV
`("v"^2rho)/T`
`T/("v"^2rho)`
Tv2ρ
MCQ
Fill in the Blanks
Solution
A uniform metal wire has length 'L', mass 'M', and density 'ρ'. It is under tension 'T' and 'v' is the speed of transverse wave along the wire. The area of cross-section A of the wire is `underline(T/("v"^2rho))`.
Explanation:
V = `sqrt(T/m)` `[m = M/L = (ALrho)/L = Arho]`
∴ V = `sqrt(T/(Arho)`
∴ `V^2 = T/(Arho)`
A = `T/(V^2rho)`
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Reflection of Waves
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