Question

A wave of frequency υ = 1000 Hz, propagates at a velocity v = 700 m/sec along x-axis. Phase difference at a given point x during a time interval M = 0.5 × 10^-3 sec is ______.

Options

• - π

• `pi/2`

• `(3pi)/2`

• 2π

Answer 1

A wave of frequency υ = 1000 Hz, propagates at a velocity v = 700 m/sec along x-axis. Phase difference at a given point x during a time interval M = 0.5 × 10^-3 sec is - π.

Explanation:

y = A sin (kx – ωt)

Φ = phase = kx – ωt

Φ₁ = kx – ωt₁

Φ₂ = kx – ωt₂

Phase: ΔΦ = Φ₂ – Φ₁ = ω(t₁ – t₂)

difference ΔΦ = Φ₂ – Φ₁ = – ω(t₂ – t₁)

ΔΦ = – ωΔt

= – 2π × 10³ × 0.5 × 10^–3

= `– 2pi × 1/2`

= – π