Question

A wheel of mass 15 kg has a moment of inertia of 200 kg-m² about its own axis, the radius of gyration will be:

Options

• 3.6 m

• 4 m

• 4.6 m

• 1.21 m

Answer 1

3.6 m

Explanation:

As we know

I = Mk² ⇒ `sqrt(1/"M") = "K" = sqrt(200/15) = sqrt(40/3) = sqrt(13.33)` = 3.65 m