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Question
A wheel of moment of inertia 2 kg m2 is rotating about an axis passing through centre and perpendicular to its plane at a speed 60 rad/s. Due to friction, it comes to rest in 5 minutes. The angular momentum of the wheel three minutes before it stops rotating is ______.
Options
24 kg m2/s
48 kg m2/s
72 kg m2/s
96 kg m2/s
Solution
A wheel of moment of inertia 2 kg m2 is rotating about an axis passing through centre and perpendicular to its plane at a speed 60 rad/s. Due to friction, it comes to rest in 5 minutes. The angular momentum of the wheel three minutes before it stops rotating is 72 kg m2/s.
Explanation:
According to question, I = 2kg m2
ω0 = 60 rad/s, ω = 0
t = 5 min = 5 × 60 = 300s
using, ω = ω0 + αt ⇒ α = `(omega-omega_0)/"t"`
= `(0-60)/300=(-60)/300=(-1)/5`rad/s2
For t = 2 min
ω = ω0 + αt
= `60-1/5xx120` = 60 - 24 ⇒ ω = 36 rad/s
Angular momentum,
L = 1ω = 2 × 36 = 72 kg m2/s