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Question
A wire of length L carrying a current I is bent into a circle. The magnitude of the magnetic field at the centre of the circle is ____________.
Options
`(pi mu_0 "I")/"L"`
`(mu_0 "I")/(2"L")`
`(2pi mu_0 "I")/"L"`
`(mu_0 "I")/(2pi "L")`
MCQ
Fill in the Blanks
Solution
A wire of length L carrying a current I is bent into a circle. The magnitude of the magnetic field at the centre of the circle is `(pi mu_0 "I")/"L"`.
Explanation:
`"Magnetic field at the centre of coil B" = (mu_0 "nI")/(2"r")`
`"n" = 1 "and" 2pi"r" = "L" Rightarrow "r" = "L"/(2pi)`
`therefore "B" = (mu_0 2 pi "I")/(2"L")`
` = (pimu_0 "I")/"L"`
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