Question

`"A" = abs ((1/"a", "a"^2, "bc"),(1/"b", "b"^2, "ac"),(1/"c", "c"^2, "ab"))` is equal to ____________.

Options

• None of these

• 1

• 0

• -1

Answer 1

`"A" = abs ((1/"a", "a"^2, "bc"),(1/"b", "b"^2, "ac"),(1/"c", "c"^2, "ab"))` is equal to 0.

Explanation:

`abs ((1/"a", "a"^2, "bc"),(1/"b", "b"^2, "ac"),(1/"c", "c"^2, "ab"))`

Apply, R₁→ aR₁, R₂ → bR, R₃ → cR₃

`=> abs ((1, "a"^3, "abc"),(1, "b"^3, "abc"),(1, "c"^3, "abc"))`

`=>"abc" abs ((1, "a"^3, 1),(1, "b"^3, 1),(1, "c"^3, 1))`

C₁ and C₃ identical

`=> 0`