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Question
`[(bar"a", bar"b" + bar"c", bar"a" + bar"b" + bar"c")]` = ______.
Options
0
`[(bar"a", bar"b", bar"c")]`
`2[(bar"a", bar"b", bar"c")]`
`3[(bar"a", bar"b", bar"c")]`
MCQ
Fill in the Blanks
Solution
`[(bar"a", bar"b" + bar"c", bar"a" + bar"b" + bar"c")]` = 0.
Explanation:
`[(bar"a", bar"b" + bar"c", bar"a" + bar"b" + bar"c")]`
= `bar"a" * [(bar"b" + bar"c") xx (bar"a" + bar"b" + bar"c")]`
= `bar"a" * [bar"b" xx bar"a" + bar"b" xx bar"b" + bar"b" xx bar"c" + bar"c" xx bar"a" + bar"c" xx bar"b" + bar"c" xx bar"c"]`
= `bar"a"*[bar"b" xx bar"a" + bar0 + bar"b" xx bar"c" + bar"c" xx bar"a" - bar"b" xx bar"c" + bar0]`
= `bar"a"*[bar"b" xx bar"a" + bar"c" xx bar"a"]`
= `bar"a"*(bar"b" xx bar"a") + bar"a"*(bar"c" xx bar"a")`
= `[(bar"a", bar"b", bar"a")] + [(bar"a", bar"c", bar"a")]` = 0
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