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Question
`bar"a" xx (bar"b" xx bar"c") + bar"b" xx (bar"c" xx bar"a") + bar"c" xx (bar"a" xx bar"b")` = ?
Options
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MCQ
Solution
0
Explanation:
`bar"a" xx (bar"b" xx bar"c") + bar"b" xx (bar"c" xx bar"a") + bar"c" xx (bar"a" xx bar"b")`
= `[(bar"a"*bar"c")bar"b" - (bar"a"*bar"b")bar"c"] + [(bar"b" * bar"a")bar"c" - (bar"b"*bar"c")bar"a"] + [(bar"c"*bar"b")bar"a" - (bar"c"*bar"a")bar"b"]`
= `(bar"a"*bar"c")bar"b" - (bar"a" * bar"b")bar"c" + (bar"a"*bar"b")bar"c" - (bar"b"*bar"c")bar"a" + (bar"b"*bar"c")bar"a" - (bar"a"*bar"c")bar"b"`
= 0
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