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Question
According to Bohr model, magnetic field at centre (at the nucleus) of a hydrogen atom due to motion of electron in the ninth orbit is proportional to:
Options
`1/"n"^3`
`1/"n"^5`
n5
n3
MCQ
Solution
`bb(1/"n"^5)`
Explanation:
B = `(mu_0"i")/(2"r")`; magnetic field at centre of hydrogen atom i.e. at nucleus.
i = `"e"/"T"` = ef = α `"z"^2/"n"^3`
r ∝ `"n"^2/"Z"`
B ∝ `"i"/"r"alpha"Z"^3/"n"^5`
B ∝ `1/"n"^5`
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